Oracle如何找出一个表的间接授权信息?

阙忆然 · 2025-9-25 21:00:10

在Oracle数据库中, 如果需要找出一张表授权给了哪一个用户,这个比较简单的,如果有一些视图引用了这张表,然后这张视图授权给了其它用户的话, 那么这也属于这张表的授权信息,如果也要找出这类信息,那么如何找出来这些信息呢?
下面简单看一个例子, 在数据库中存在三个用户T1, T2, T3, 假设T1用户将表T1.TEST的查询权限授予了用户T2.

create user t1 identified by t123456; create user t2 identified by t234561; create user t3 identified by t345612; alter user t1 quota unlimited on users; alter user t2 quota unlimited on users; alter user t3 quota unlimited on users; grant connect, resource to t1; grant connect, resource to t2; grant connect, resource to t3; grant create view to t2; grant create view to t3;

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具体授权操作如下所示:

SQL> show user; USER is "T1" SQL> create table test(id number(10), name varchar2(30)); Table created. SQL> insert into test 2 select 1, 'k1' from dual union all 3 select 2, 'k2' from dual; 2 rows created. SQL> commit; Commit complete. SQL> SQL> grant select on test to t2; Grant succeeded

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那么此时查看关于表TEST的授权信息如下所示:

SET LINESIZE 820; COL GRANTEE FOR A12 COL OWNER FOR A12 COL TABLE_NAME FOR A12 COL GRANTOR FOR A12 COL PRIVILEGE FOR A12 SELECT OWNER, TABLE_NAME, GRANTOR , GRANTEE, PRIVILEGE, GRANTABLE, TYPE FROM DBA_TAB_PRIVS WHERE TABLE_NAME='TEST';

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SQL> show user; USER is "SYS" SQL> SET LINESIZE 820; SQL> COL GRANTEE FOR A12 SQL> COL OWNER FOR A12 SQL> COL TABLE_NAME FOR A12 SQL> COL GRANTOR FOR A12 SQL> COL PRIVILEGE FOR A12 SQL> SELECT OWNER, TABLE_NAME, GRANTOR , GRANTEE, PRIVILEGE, GRANTABLE, TYPE 2 FROM DBA_TAB_PRIVS WHERE TABLE_NAME='TEST'; OWNER TABLE_NAME GRANTOR GRANTEE PRIVILEGE GRA TYPE ------------ ------------ ------------ ------------ ------------ --- ------------------------ T1 TEST T1 T2 SELECT NO TABLE SQL>

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如果用户T1将表TEST的查询权限授予了用户T2,并且使用了选项GRANT OPTION的话

SQL> show user; USER is "T1" SQL> grant select on test to t2 with grant option; Grant succeeded. SQL>

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那么此时,如果在T2用户下面创建一个视图,引用表TEST, 然后将视图T2.V_TEST的查询权限授权给了用户T3.

SQL> show user; USER is "T2" SQL> create or replace view v_test 2 as 3 select name from t1.test; View created. SQL> grant select on t2.v_test to t3; Grant succeeded. SQL>

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此时用户T3就相当间接拥有了表TEST的查询权限. 如下所示:

SQL> show user; USER is "T3" SQL> select * from t2.v_test; NAME ------------------------------ k1 k2 SQL>

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但是,我们用上面的SQL来查询一下表TEST授予了哪些用户.如下所示, 这个查询结果不能体现表TEST间接授权给了用户T3

SQL> show user; USER is "SYS" SQL> SET LINESIZE 820; SQL> COL GRANTEE FOR A12 SQL> COL OWNER FOR A12 SQL> COL TABLE_NAME FOR A12 SQL> COL GRANTOR FOR A12 SQL> COL PRIVILEGE FOR A12 SQL> SELECT OWNER, TABLE_NAME, GRANTOR , GRANTEE, PRIVILEGE, GRANTABLE, TYPE 2 FROM DBA_TAB_PRIVS WHERE TABLE_NAME='TEST'; OWNER TABLE_NAME GRANTOR GRANTEE PRIVILEGE GRA TYPE ------------ ------------ ------------ ------------ ------------ --- ------------------------ T1 TEST T1 T2 SELECT YES TABLE SQL>

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那么问题来了,如何查询这种情况下的授权呢? 其实我们可以用下面SQL实现这个需求.如下所示:

SET LINESIZE 820 COL OWNER FOR A10 COL TABLE_NAME FOR A16; COL GRANTOR FOR A16 COL GRANTEE FOR A16 COL PRIVILEGE FOR A8; SELECT OWNER, TABLE_NAME, GRANTOR , GRANTEE, PRIVILEGE, GRANTABLE, TYPE FROM DBA_TAB_PRIVS WHERE TABLE_NAME=UPPER(TRIM('&tb_name')) UNION ALL SELECT OWNER, TABLE_NAME, GRANTOR , GRANTEE, PRIVILEGE, GRANTABLE, TYPE FROM DBA_TAB_PRIVS WHERE TABLE_NAME IN( SELECT NAME FROM dba_dependencies WHERE REFERENCED_NAME=UPPER(TRIM('&tb_name')) AND TYPE='VIEW' );

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Oracle如何找出一个表的间接授权信息?

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